C++ Program to determine whether a number is even or odd

Friends , Today I am going to publish a Simple program to find whether a number is even or odd.








Hello Cyber Astronauts,
In this article I will tell you How to write a program that determines whether a number is odd or even.



First we need to know,

Integers which are perfectly divisible by 2 are called even numbers. And those integers which are not perfectly divisible by 2 are not known as odd number. To check whether an integer is even or odd, the remainder is calculated when it is divided by 2 using modulus operator %. If remainder is zero, that integer is even if not that integer is odd.

In this program, if..else statement is used to check whether n%2 == 0 is true or not. If this expression is true, n is even if not n is odd.

#include<iostream.h>
#include<conio.h>
#include<math.h>
void main()
{  clrscr();
int n;
cout<<"Enter any number :";
cin>>n;
if(n%2==0)
cout<<"The number "<<n<<" is even ";
else
cout<<"The number "<<n<<" is odd :";
getch();
}
                               

                                                         ::OUTPUT::1::



                                                          ::OUTPUT::2



If got stuck in any problem, feel free to comment below.

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Hey Cyber Astronauts, Welcome to the one of best blog The CyberSpace HUB. I'm Himanshu Singh, a Part-time-blogger from India. Here at The CyberSpace HUB I write about Starting and managing a blog,Latest technology and Making Money online.


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